Cut out selected fields of each line of a file (POSIX)
cut -c list [file...] cut -f list [-d delim] [-s] [file...]
- -c list
- Cut out the characters found in the character positions specified by list. For example, a list of -c 1-64 outputs the first 64 characters of each line.
- -d delim
- Use the delimiter specified by delim (default is tab).
- -f list
- Cut out the fields specified by list. For example, -f 2,9 outputs the second and ninth fields. The fields described by list are assumed to be separated in the file by a delimiter character (see option -d). Lines without field delimiters are passed through intact, unless -s is specified.
- If -f is specified, suppress lines with no field delimiters.
- The pathname of a text file, whose contents are used instead of the standard input.
For every file you name, the cut utility cuts out columns or fields from each line, concatenates them, and writes them to the standard output.
If the fields are of a fixed length, you can select them by character position with option -c. If, however, the fields vary in length from line to line, you can select them with the -f option, provided they're separated by a delimiter character. By default, cut assumes the field delimiter character to be tab. You can use the -d option to specify another delimiter.
In options -c and -f, list is a comma-separated list of integers (in increasing order), with an optional dash (-) to indicate ranges.
You can use the cut utility as a filter; if no files are given, the standard input is used.
The following are examples of the list argument:
|1,4,7||Select the first, fourth, and seventh characters or fields.|
|1-3,8||Equivalent to 1, 2, 3, 8.|
|-5,10||Equivalent to 1, 2, 3, 4, 5, 10.|
|3-||Equivalent to the third through last.|
Map userids to names:
cut -d: -f1,5 /etc/passwd
List filenames and their permissions:
ls -l | cut -c57-79,56,56,1-11
- All input files were output successfully.
- An error occurred.